The solubility constant of stronyium sulfate, srso4, is 2.8 x 10-7. how many grams of srso4 must be dissolved in water to produce 1 l saturated solution? Answer: The answer is 0.1 g of Strontium Sulfate . Step-by-step explanation: Solubility constant is solved using the equation below (Eqn 1) Where is the molar solubility of the cation and is the molar solubility of the anion. Based from our problem our solution goes like this Take note that s= because their stoichiometric ratio is 1:1. Next, we need to convert the molar solubility to mass solubility Using the molar mass of , we have Thus in order to saturate 1 L of solution we need 0.0972 g of or approximately 0.1 g . If you want to know more about solubility, you may visit the following links: brainly.ph/question/1289331 brainly.ph/question/1113977 brainly.ph/question/1113850
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